-600=50x^2-402x+95.52

Solution for -600=50x^2-402x+95.52 equation:

-600=50x^2-402x+95.52

We move all terms to the left:

-600-(50x^2-402x+95.52)=0

We get rid of parentheses

-50x^2+402x-95.52-600=0

We add all the numbers together, and all the variables

-50x^2+402x-695.52=0

a = -50; b = 402; c = -695.52;
Δ = b2-4ac
Δ = 4022-4·(-50)·(-695.52)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(402)-150}{2*-50}=\frac{-552}{-100}
=5+13/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(402)+150}{2*-50}=\frac{-252}{-100}
=2+13/25
$